(2x^2+2)+(x^2-4)-(3x^2+1)=

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Solution for (2x^2+2)+(x^2-4)-(3x^2+1)= equation:


Simplifying
(2x2 + 2) + (x2 + -4) + -1(3x2 + 1) = 0

Reorder the terms:
(2 + 2x2) + (x2 + -4) + -1(3x2 + 1) = 0

Remove parenthesis around (2 + 2x2)
2 + 2x2 + (x2 + -4) + -1(3x2 + 1) = 0

Reorder the terms:
2 + 2x2 + (-4 + x2) + -1(3x2 + 1) = 0

Remove parenthesis around (-4 + x2)
2 + 2x2 + -4 + x2 + -1(3x2 + 1) = 0

Reorder the terms:
2 + 2x2 + -4 + x2 + -1(1 + 3x2) = 0
2 + 2x2 + -4 + x2 + (1 * -1 + 3x2 * -1) = 0
2 + 2x2 + -4 + x2 + (-1 + -3x2) = 0

Reorder the terms:
2 + -4 + -1 + 2x2 + x2 + -3x2 = 0

Combine like terms: 2 + -4 = -2
-2 + -1 + 2x2 + x2 + -3x2 = 0

Combine like terms: -2 + -1 = -3
-3 + 2x2 + x2 + -3x2 = 0

Combine like terms: 2x2 + x2 = 3x2
-3 + 3x2 + -3x2 = 0

Combine like terms: 3x2 + -3x2 = 0
-3 + 0 = 0
-3 = 0

Solving
-3 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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